Process 1: \begin{align*} P(X(t + \Delta t) = y \,|\, X(t) = x) = \begin{cases} a \Delta t & \text{if $y=x+1$}\\ 1-(a+b)\Delta t & \text{if $y=x$}\\ b \Delta t & \text{if $y=x-1$}\\ 0 & \text{otherwise} \end{cases} \end{align*}
Process 2: \begin{align*} P(X(t + \Delta t) = y \,|\, X(t) = x) = \begin{cases} a x \Delta t & \text{if $y=x+1$}\\ 1-(a+b)x\Delta t & \text{if $y=x$}\\ b x\Delta t & \text{if $y=x-1$}\\ 0 & \text{otherwise} \end{cases} \end{align*}
Under what conditions is the deterministic model a poor approximation to the stochastic model? What features of the stochastic model are completely missed by the deterministic model?