Let $g(y) = - 2 y^{3} + 1$.
Calculate the slope of the secant line from $y=-1$ to $y=-9$.
Slope =
Calculate the slope of the secant line from $y=k$ to $y=d$.
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Given the function \[ h( y ) = \ln{\left (y^{2} + 7 y - 8 \right )}, \] calculate the slope of the tangent line at the point $y=-4$.
tangent line slope =
Do not round or approximate your answer.