Let $g(z) = - 8 z^{3} - 4$.
Calculate the slope of the secant line from $z=-8$ to $z=-7$.
Slope =
Calculate the slope of the secant line from $z=k$ to $z=c$.
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Given the function \[ g( x ) = \ln{\left (x^{2} - 14 x + 48 \right )}, \] calculate the slope of the tangent line at the point $x=3$.
tangent line slope =
Do not round or approximate your answer.