For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.7\\0.5\\2.0\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.76\\1.99\\2.33\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.806\\3.261\\3.233\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.185\\4.88\\4.682\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}6.157\\7.182\\6.843\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}9.031\\10.54\\10.02\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}13.24\\15.45\\14.69\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}19.41\\22.64\\21.53\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}28.44\\33.18\\31.56\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}41.69\\48.64\\46.25\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}61.1\\71.29\\67.79\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.1\\0.7\\1.6\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.04\\1.33\\1.71\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.858\\2.191\\2.259\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.842\\3.32\\3.221\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}4.206\\4.908\\4.69\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}6.179\\7.209\\6.863\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}9.061\\10.57\\10.06\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}13.28\\15.5\\14.74\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}19.47\\22.71\\21.6\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}28.53\\33.29\\31.66\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}41.82\\48.79\\46.4\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 120\\5\end{bmatrix}$.