For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.8\\1.2\\0.3\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}3.03\\1.05\\1.14\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.642\\2.175\\2.166\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}6.168\\3.763\\3.764\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}10.61\\6.504\\6.503\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}18.31\\11.23\\11.23\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}31.61\\19.38\\19.38\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}54.57\\33.46\\33.46\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}94.19\\57.75\\57.75\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}162.6\\99.69\\99.69\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}280.7\\172.1\\172.1\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.6\\0.3\\0.7\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.52\\1.18\\1.14\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.108\\1.912\\1.916\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.379\\3.303\\3.302\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}9.295\\5.699\\5.699\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}16.05\\9.838\\9.838\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}27.7\\16.98\\16.98\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}47.81\\29.32\\29.32\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}82.54\\50.6\\50.6\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}142.5\\87.35\\87.35\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}245.9\\150.8\\150.8\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 140\\5\end{bmatrix}$.
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