For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.2\\0.0\\0.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.52\\0.22\\0.36\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.69\\0.632\\0.5\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.18\\1.253\\0.9556\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}2.26\\2.381\\1.863\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}4.354\\4.546\\3.581\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}8.351\\8.707\\6.86\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}16.0\\16.68\\13.14\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}30.64\\31.96\\25.17\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}58.7\\61.22\\48.22\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}112.5\\117.3\\92.38\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.3\\1.5\\0.6\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.83\\2.13\\1.74\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.945\\3.993\\3.27\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}7.508\\7.745\\6.137\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}14.29\\14.89\\11.72\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}27.34\\28.53\\22.46\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}52.39\\54.64\\43.04\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}100.4\\104.7\\82.45\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}192.3\\200.5\\157.9\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}368.4\\384.2\\302.6\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}705.7\\735.9\\579.6\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 80\\2\end{bmatrix}$.