For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.5\\0.7\\0.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.72\\3.36\\0.97\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.579\\5.933\\1.935\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}0.8121\\9.549\\3.612\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}1.408\\15.44\\6.535\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}2.524\\25.45\\11.63\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}4.498\\42.68\\20.49\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}7.946\\72.48\\35.9\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}13.95\\124.1\\62.69\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}24.39\\213.6\\109.2\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}42.53\\368.9\\190.1\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.7\\0.2\\1.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.13\\3.56\\2.61\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.235\\7.628\\4.497\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.843\\14.02\\7.755\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}3.064\\24.86\\13.4\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}5.247\\43.62\\23.2\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}9.06\\76.18\\40.22\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}15.69\\132.7\\69.76\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}27.2\\231.0\\121.0\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}47.19\\401.6\\210.1\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}81.91\\697.9\\364.8\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 60\\4\end{bmatrix}$.