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Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 90\\3\end{bmatrix}$.
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.7\\0.6\\0.6\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.78\\1.13\\1.27\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.215\\2.196\\1.723\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.309\\3.026\\2.503\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}4.765\\4.388\\3.616\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}6.884\\6.339\\5.222\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}9.944\\9.156\\7.544\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}14.36\\13.23\\10.9\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}20.75\\19.11\\15.74\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}29.97\\27.6\\22.74\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}43.3\\39.87\\32.85\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.3\\2.0\\0.7\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.64\\1.28\\1.16\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.208\\2.032\\1.68\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.189\\2.944\\2.421\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}4.612\\4.245\\3.498\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}6.661\\6.133\\5.053\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}9.622\\8.859\\7.299\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}13.9\\12.8\\10.54\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}20.08\\18.49\\15.23\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}29.0\\26.7\\22.0\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}41.89\\38.57\\31.78\end{matrix}\right]\end{gather*}