For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.5\\0.4\\0.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.33\\0.84\\1.09\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.771\\1.939\\2.029\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.488\\4.135\\4.493\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}3.258\\8.934\\9.571\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}6.962\\19.21\\20.65\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}15.0\\41.34\\44.39\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}32.27\\88.95\\95.54\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}69.45\\191.4\\205.6\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}149.4\\411.9\\442.4\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}321.5\\886.3\\951.9\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.5\\1.0\\0.7\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.57\\1.89\\2.23\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.584\\4.207\\4.39\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.213\\8.963\\9.7\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}7.038\\19.34\\20.72\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}15.07\\41.58\\44.68\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}32.47\\89.49\\96.09\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}69.85\\192.5\\206.8\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}150.3\\414.3\\445.0\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}323.5\\891.6\\957.5\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}696.0\\1918.0\\2060.0\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 170\\5\end{bmatrix}$.
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