Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 140\\4\end{bmatrix}$.
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.4\\0.4\\1.9\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.39\\1.63\\1.4\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.459\\1.859\\1.928\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}0.5623\\2.304\\2.346\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}0.6899\\2.826\\2.883\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}0.8468\\3.469\\3.538\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}1.039\\4.258\\4.343\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}1.276\\5.226\\5.331\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}1.566\\6.415\\6.544\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}1.922\\7.874\\8.032\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}2.36\\9.665\\9.86\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.2\\0.4\\1.2\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.64\\2.32\\1.92\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.68\\2.72\\2.8\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}0.824\\3.372\\3.432\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}1.01\\4.136\\4.22\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}1.24\\5.077\\5.18\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}1.522\\6.232\\6.358\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}1.868\\7.65\\7.804\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}2.292\\9.39\\9.579\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}2.814\\11.53\\11.76\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}3.454\\14.15\\14.43\end{matrix}\right]\end{gather*}