For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.5\\1.7\\1.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.71\\2.84\\1.27\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.083\\4.543\\2.888\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.156\\8.265\\5.329\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}9.208\\14.69\\9.128\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}16.35\\25.87\\16.18\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}28.85\\45.76\\28.69\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}51.02\\80.96\\50.69\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}90.25\\143.1\\89.63\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}159.6\\253.1\\158.5\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}282.2\\447.6\\280.3\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.7\\0.8\\0.2\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.94\\1.35\\1.05\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.561\\2.631\\1.672\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.896\\4.584\\2.794\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}5.105\\8.051\\5.062\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}8.989\\14.28\\8.961\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}15.92\\25.25\\15.8\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}28.15\\44.64\\27.96\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}49.77\\78.95\\49.45\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}88.01\\139.6\\87.43\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}155.6\\246.9\\154.6\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 120\\4\end{bmatrix}$.
Hide help