For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.5\\0.0\\0.3\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.76\\0.61\\0.09\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.082\\0.732\\0.881\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.698\\1.555\\1.289\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}4.94\\3.216\\2.564\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}9.724\\6.069\\5.272\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}19.29\\12.08\\10.08\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}37.64\\23.69\\19.93\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}74.02\\46.44\\39.15\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}145.4\\91.27\\76.75\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}285.3\\179.1\\150.8\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.3\\1.7\\0.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.36\\0.69\\2.5\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}6.051\\3.707\\1.716\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}9.279\\6.413\\5.705\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}20.11\\12.06\\10.69\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}39.08\\24.78\\20.09\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}75.99\\47.8\\40.71\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}150.2\\94.07\\79.13\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}294.3\\185.0\\155.4\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}577.9\\362.7\\305.6\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}1135.0\\712.5\\599.5\end{matrix}\right]\end{gather*}
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Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 60\\5\end{bmatrix}$.