Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 120\\2\end{bmatrix}$.
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.9\\1.6\\2.0\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.45\\2.68\\4.06\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}4.097\\3.974\\6.938\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}6.49\\6.356\\10.75\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}10.26\\10.08\\17.04\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}16.25\\15.96\\27.01\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}25.74\\25.28\\42.78\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}40.78\\40.04\\67.76\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}64.59\\63.42\\107.3\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}102.3\\100.5\\170.0\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}162.1\\159.1\\269.3\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.4\\2.0\\0.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.26\\2.4\\4.2\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.858\\3.668\\6.452\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}6.027\\5.932\\9.955\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}9.541\\9.377\\15.87\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}15.12\\14.85\\25.13\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}23.95\\23.52\\39.8\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}37.94\\37.25\\63.04\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}60.1\\59.01\\99.86\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}95.2\\93.47\\158.2\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}150.8\\148.1\\250.6\end{matrix}\right]\end{gather*}