For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.8\\0.1\\1.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.58\\3.47\\1.26\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.562\\2.837\\4.41\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.603\\4.386\\6.08\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}2.236\\5.24\\8.803\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}2.767\\6.867\\11.63\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}3.577\\8.69\\15.28\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}4.549\\11.14\\19.74\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}5.821\\14.21\\25.42\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}7.432\\18.17\\32.59\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}9.496\\23.2\\41.72\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.8\\0.7\\0.0\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.82\\3.77\\0.88\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.754\\3.443\\4.468\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.903\\5.054\\6.746\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}2.593\\6.143\\9.967\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}3.235\\7.998\\13.38\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}4.17\\10.15\\17.69\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}5.309\\13.0\\22.94\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}6.791\\16.59\\29.59\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}8.671\\21.2\\37.98\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}11.08\\27.07\\48.65\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 150\\3\end{bmatrix}$.