For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.8\\1.8\\1.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}3.06\\2.91\\1.92\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}4.386\\4.512\\2.76\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}6.433\\6.744\\3.962\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}9.382\\9.949\\5.743\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}13.69\\14.58\\8.347\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}19.96\\21.32\\12.15\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}29.1\\31.11\\17.7\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}42.42\\45.38\\25.8\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}61.84\\66.17\\37.61\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}90.15\\96.48\\54.82\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.2\\1.5\\0.1\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.08\\1.73\\0.56\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.688\\2.096\\0.88\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.401\\2.792\\1.379\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}3.492\\3.884\\2.064\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}5.077\\5.535\\3.048\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}7.395\\7.983\\4.469\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}10.77\\11.58\\6.533\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}15.7\\16.84\\9.536\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}22.89\\24.52\\13.91\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}33.37\\35.73\\20.28\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 100\\3\end{bmatrix}$.