Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 60\\5\end{bmatrix}$.
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For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.1\\1.2\\1.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.43\\1.96\\3.92\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.691\\3.814\\7.114\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.022\\7.044\\13.19\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}9.298\\13.05\\24.46\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}17.24\\24.2\\45.34\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}31.96\\44.86\\84.05\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}59.25\\83.17\\155.8\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}109.8\\154.2\\288.9\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}203.6\\285.9\\535.5\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}377.5\\529.9\\992.8\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.8\\1.7\\0.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.25\\1.4\\2.87\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.973\\2.819\\5.387\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.762\\5.293\\9.872\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}6.971\\9.78\\18.33\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.92\\18.13\\33.98\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}23.95\\33.62\\62.99\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}44.4\\62.33\\116.8\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}82.31\\115.5\\216.5\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}152.6\\214.2\\401.3\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}282.9\\397.1\\744.0\end{matrix}\right]\end{gather*}