For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.2\\0.1\\0.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.43\\0.92\\0.4\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.725\\1.177\\0.869\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.263\\2.164\\1.411\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}2.17\\3.65\\2.462\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}3.737\\6.307\\4.221\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}6.429\\10.84\\7.268\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}11.06\\18.65\\12.5\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}19.04\\32.1\\21.52\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}32.76\\55.23\\37.02\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}56.37\\95.04\\63.71\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.1\\0.0\\1.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.93\\3.47\\1.75\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.17\\5.017\\3.689\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.464\\9.258\\6.099\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}9.376\\15.75\\10.62\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}16.14\\27.21\\18.22\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}27.76\\46.8\\31.38\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}47.77\\80.54\\53.99\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}82.2\\138.6\\92.9\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}141.4\\238.5\\159.9\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}243.4\\410.3\\275.1\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 130\\3\end{bmatrix}$.