For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.2\\0.0\\1.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.08\\0.86\\2.22\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.746\\1.386\\3.808\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.819\\2.26\\6.349\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}4.571\\3.682\\10.45\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}7.428\\5.997\\17.12\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}12.08\\9.767\\27.94\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}19.66\\15.9\\45.56\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}32.01\\25.9\\74.23\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}52.12\\42.17\\120.9\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}84.86\\68.66\\196.9\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.6\\0.6\\0.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.08\\0.77\\1.59\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.665\\1.269\\3.142\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.641\\2.075\\5.556\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}4.244\\3.385\\9.395\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}6.866\\5.516\\15.57\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}11.14\\8.987\\25.58\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}18.12\\14.64\\41.82\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}29.48\\23.83\\68.23\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}47.98\\38.81\\111.2\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}78.11\\63.2\\181.2\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 150\\3\end{bmatrix}$.