For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.2\\1.5\\0.1\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.17\\2.15\\0.62\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.228\\3.972\\1.685\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.46\\7.506\\3.828\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}8.889\\14.54\\8.12\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}17.71\\28.52\\16.69\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}35.3\\56.36\\33.8\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}70.32\\111.8\\67.91\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}140.1\\222.2\\135.9\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}279.1\\442.1\\271.3\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}556.0\\880.2\\541.2\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.4\\1.9\\1.9\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.89\\4.11\\3.32\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}5.736\\8.608\\6.127\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}11.42\\17.58\\11.69\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}22.75\\35.47\\22.76\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}45.31\\71.14\\44.78\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}90.26\\142.2\\88.62\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}179.8\\283.8\\175.9\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}358.2\\566.0\\349.8\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}713.5\\1128.0\\696.2\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}1421.0\\2248.0\\1386.0\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 50\\4\end{bmatrix}$.