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For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.2\\1.9\\1.0\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.81\\0.88\\4.28\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.691\\0.861\\5.251\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.147\\1.139\\6.558\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}8.398\\1.626\\8.84\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.94\\2.374\\12.52\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}19.47\\3.495\\18.17\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}29.04\\5.162\\26.67\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}43.13\\7.636\\39.34\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}63.94\\11.3\\58.15\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}94.72\\16.73\\86.05\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.8\\1.3\\1.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.83\\0.88\\4.32\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}4.929\\1.067\\5.889\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}7.884\\1.509\\8.11\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}12.07\\2.203\\11.57\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}18.12\\3.245\\16.84\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}27.0\\4.794\\24.75\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}40.07\\7.092\\36.53\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}59.4\\10.5\\54.01\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}88.0\\15.54\\79.92\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}130.3\\23.01\\118.3\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 70\\4\end{bmatrix}$.