For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.4\\0.8\\0.2\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.08\\1.32\\0.34\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.004\\2.28\\0.562\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.5\\3.92\\0.9682\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}6.048\\6.755\\1.665\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}10.43\\11.64\\2.869\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}17.97\\20.05\\4.942\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}30.95\\34.54\\8.514\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}53.33\\59.51\\14.67\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}91.88\\102.5\\25.27\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}158.3\\176.7\\43.54\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.3\\0.2\\1.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.49\\3.0\\0.22\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.909\\4.194\\1.222\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}6.776\\7.595\\1.8\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}11.62\\12.95\\3.218\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}20.03\\22.36\\5.501\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}34.51\\38.51\\9.495\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}59.45\\66.35\\16.35\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}102.4\\114.3\\28.17\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}176.5\\196.9\\48.54\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}304.0\\339.3\\83.63\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 60\\5\end{bmatrix}$.