For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.9\\0.8\\1.1\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.47\\3.0\\0.89\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.637\\3.786\\2.225\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.44\\6.574\\3.08\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}8.337\\9.785\\5.105\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.8\\15.41\\7.726\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}19.74\\23.63\\12.07\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}30.45\\36.6\\18.56\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}47.0\\56.43\\28.72\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}72.55\\87.16\\44.3\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}112.0\\134.5\\68.41\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.7\\0.8\\1.3\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.33\\3.12\\0.91\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.539\\3.75\\2.287\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.35\\6.575\\3.061\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}8.241\\9.697\\5.093\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.68\\15.3\\7.661\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}19.57\\23.42\\11.98\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}30.19\\36.3\\18.41\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}46.6\\55.95\\28.48\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}71.92\\86.42\\43.92\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}111.0\\133.4\\67.83\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 60\\2\end{bmatrix}$.