For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.5\\0.2\\0.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.74\\0.09\\1.56\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.147\\0.174\\2.47\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.833\\0.2818\\3.924\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}2.918\\0.4487\\6.243\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}4.643\\0.714\\9.934\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}7.389\\1.136\\15.81\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}11.76\\1.808\\25.15\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}18.71\\2.877\\40.02\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}29.77\\4.578\\63.69\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}47.37\\7.284\\101.3\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.6\\1.1\\1.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.17\\0.4\\4.02\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.126\\0.482\\6.631\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.941\\0.7595\\10.57\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}7.861\\1.209\\16.82\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.51\\1.924\\26.76\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}19.9\\3.061\\42.58\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}31.67\\4.87\\67.76\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}50.4\\7.75\\107.8\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}80.2\\12.33\\171.6\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}127.6\\19.62\\273.0\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 90\\3\end{bmatrix}$.