For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.1\\0.4\\1.9\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.49\\1.65\\1.78\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.091\\1.968\\3.11\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.85\\3.288\\4.551\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}6.752\\5.012\\7.187\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}11.09\\7.928\\11.22\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}17.91\\12.46\\17.68\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}28.58\\19.68\\27.88\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}45.4\\31.06\\44.02\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}71.92\\49.07\\69.52\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}113.8\\77.53\\109.8\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.3\\0.4\\1.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.57\\1.45\\1.62\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.863\\1.888\\2.886\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.465\\3.161\\4.383\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}7.18\\4.902\\6.992\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}11.36\\7.782\\11.0\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}18.01\\12.27\\17.4\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}28.48\\19.4\\27.48\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}45.04\\30.66\\43.43\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}71.19\\48.44\\68.63\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}112.5\\76.55\\108.4\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 110\\4\end{bmatrix}$.