For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.7\\1.9\\0.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.08\\3.07\\1.98\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.245\\4.394\\2.866\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.692\\5.937\\3.938\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}2.288\\8.112\\5.358\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}3.12\\11.03\\7.297\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}4.244\\15.02\\9.931\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}5.779\\20.44\\13.52\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}7.865\\27.82\\18.4\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}10.71\\37.87\\25.05\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}14.57\\51.55\\34.1\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.7\\0.8\\0.2\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.75\\2.61\\1.44\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.008\\3.225\\2.214\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.27\\4.612\\3.002\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}1.765\\6.175\\4.108\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}2.382\\8.458\\5.583\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}3.252\\11.49\\7.604\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}4.422\\15.65\\10.35\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}6.022\\21.3\\14.09\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}8.195\\28.99\\19.18\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}11.16\\39.46\\26.1\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 120\\4\end{bmatrix}$.