For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.5\\1.1\\0.9\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.22\\2.05\\1.43\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.364\\3.705\\2.496\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.361\\6.666\\4.456\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}7.926\\11.99\\8.001\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}14.33\\21.57\\14.39\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}25.84\\38.83\\25.89\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}46.55\\69.88\\46.59\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}83.82\\125.8\\83.85\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}150.9\\226.4\\150.9\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}271.6\\407.5\\271.7\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.3\\0.4\\1.6\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.58\\1.66\\1.55\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.82\\3.393\\2.394\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.735\\6.311\\4.233\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}8.122\\11.48\\7.647\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}14.24\\20.76\\13.82\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}25.29\\37.43\\24.93\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}45.24\\67.43\\44.94\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}81.19\\121.4\\80.93\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}145.9\\218.6\\145.7\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}262.5\\393.5\\262.3\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 90\\4\end{bmatrix}$.