Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 130\\5\end{bmatrix}$.
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.1\\0.5\\1.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.53\\2.09\\1.26\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.097\\3.289\\2.862\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.218\\6.414\\5.092\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}4.321\\12.2\\9.806\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}8.367\\23.49\\18.79\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}16.15\\45.23\\36.19\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}31.14\\87.16\\69.72\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}60.03\\168.0\\134.4\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}115.7\\323.8\\258.9\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}223.0\\624.0\\499.1\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.4\\0.7\\2.0\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.95\\2.9\\1.79\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.788\\4.966\\4.181\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.478\\9.782\\7.751\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}6.703\\18.76\\15.03\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.93\\36.18\\28.93\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}24.91\\69.72\\55.77\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}48.02\\134.4\\107.5\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}92.56\\259.0\\207.2\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}178.4\\499.2\\399.3\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}343.9\\962.1\\769.5\end{matrix}\right]\end{gather*}