For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.2\\1.6\\1.7\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.78\\4.78\\1.09\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.022\\6.862\\1.955\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}2.87\\9.228\\2.579\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}3.905\\12.65\\3.539\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}5.34\\17.28\\4.836\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}7.3\\23.62\\6.61\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}9.978\\32.29\\9.036\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}13.64\\44.14\\12.35\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}18.64\\60.34\\16.88\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}25.49\\82.47\\23.08\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.2\\1.0\\1.0\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.8\\1.88\\0.4\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.828\\2.86\\0.816\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.19\\3.819\\1.068\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}1.617\\5.237\\1.465\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}2.212\\7.157\\2.003\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}3.023\\9.783\\2.737\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}4.132\\13.37\\3.742\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}5.649\\18.28\\5.115\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}7.721\\24.99\\6.992\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}10.55\\34.16\\9.557\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 70\\5\end{bmatrix}$.