For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.2\\0.7\\1.5\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.93\\3.98\\1.1\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}4.052\\4.347\\1.815\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}5.305\\7.336\\2.811\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}8.445\\10.8\\4.183\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.6\\16.44\\6.367\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}19.12\\24.84\\9.614\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}28.9\\37.58\\14.55\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}43.73\\56.85\\22.01\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}66.14\\85.99\\33.29\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}100.1\\130.1\\50.36\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.7\\0.4\\1.6\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.7\\3.77\\0.93\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.723\\3.804\\1.636\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.716\\6.639\\2.532\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}7.616\\9.693\\3.755\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}11.31\\14.78\\5.726\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}17.19\\22.33\\8.64\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}25.98\\33.78\\13.08\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}39.3\\51.1\\19.78\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}59.45\\77.29\\29.92\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}89.93\\116.9\\45.26\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 60\\3\end{bmatrix}$.