For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.4\\0.0\\0.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.76\\0.44\\0.48\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.924\\0.756\\0.772\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.218\\1.234\\1.295\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}1.743\\2.004\\2.135\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}2.636\\3.245\\3.485\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}4.115\\5.251\\5.661\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}6.534\\8.493\\9.173\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}10.47\\13.73\\14.85\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}16.84\\22.2\\24.01\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}27.17\\35.89\\38.83\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.1\\0.8\\0.7\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.44\\1.16\\1.3\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.046\\1.854\\2.056\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.969\\2.987\\3.273\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}3.409\\4.82\\5.249\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}5.693\\7.785\\8.452\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}9.349\\12.58\\13.63\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}15.23\\20.33\\22.02\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}24.72\\32.87\\35.58\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}40.04\\53.13\\57.5\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}64.78\\85.88\\92.94\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 130\\3\end{bmatrix}$.
Hide help