For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.9\\1.6\\1.9\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.0\\3.91\\4.19\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.868\\6.557\\6.184\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}6.219\\11.39\\10.97\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}10.77\\19.29\\18.36\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}18.2\\32.88\\31.4\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}31.02\\55.89\\53.3\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}52.73\\95.09\\90.73\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}89.71\\161.7\\154.3\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}152.6\\275.1\\262.5\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}259.5\\467.9\\446.4\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.1\\1.1\\1.9\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.61\\2.58\\2.69\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}2.602\\4.631\\4.501\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}4.42\\7.93\\7.582\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}7.496\\13.52\\12.91\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}12.76\\22.99\\21.93\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}21.69\\39.11\\37.32\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}36.9\\66.52\\63.47\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}62.76\\113.2\\108.0\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}106.8\\192.5\\183.6\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}181.6\\327.4\\312.3\end{matrix}\right]\end{gather*}
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Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 120\\3\end{bmatrix}$.