For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.6\\0.4\\0.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.3\\0.92\\0.96\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.586\\1.956\\1.804\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.217\\3.816\\3.649\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}2.395\\7.642\\7.239\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}4.784\\15.2\\14.43\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}9.521\\30.28\\28.73\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}18.97\\60.3\\57.23\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}37.77\\120.1\\114.0\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}75.22\\239.2\\227.0\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}149.8\\476.3\\452.1\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.2\\1.3\\1.3\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.9\\2.84\\2.82\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}1.792\\5.832\\5.458\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}3.641\\11.5\\10.95\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}7.209\\22.96\\21.77\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}14.38\\45.7\\43.38\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}28.63\\91.03\\86.39\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}57.02\\181.3\\172.1\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}113.5\\361.0\\342.7\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}226.1\\719.1\\682.4\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}450.4\\1432.0\\1359.0\end{matrix}\right]\end{gather*}
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Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 80\\4\end{bmatrix}$.