Hide help
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.6\\0.4\\1.8\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.86\\4.72\\2.14\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.814\\7.764\\3.52\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}1.219\\11.81\\5.129\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}1.783\\17.71\\7.759\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}2.684\\26.55\\11.59\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}4.014\\39.78\\17.39\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}6.019\\59.61\\26.04\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}9.017\\89.32\\39.03\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}13.51\\133.8\\58.48\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}20.25\\200.6\\87.63\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.8\\0.0\\0.1\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}0.39\\2.98\\1.99\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}0.675\\5.296\\2.118\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}0.7704\\7.964\\3.602\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}1.235\\12.0\\5.19\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}1.804\\17.97\\7.879\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}2.724\\26.94\\11.76\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}4.072\\40.36\\17.64\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}6.107\\60.48\\26.42\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}9.148\\90.62\\39.6\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}13.71\\135.8\\59.33\end{matrix}\right]\end{gather*}
Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 70\\3\end{bmatrix}$.