Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 90\\3\end{bmatrix}$.
For the initial condition $\vc{x}_0 = \left[\begin{matrix}0.8\\1.6\\1.1\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.7\\2.88\\1.71\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}5.598\\5.184\\3.303\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}10.89\\9.331\\6.115\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}20.43\\16.8\\11.19\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}37.61\\30.23\\20.32\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}68.55\\54.42\\36.76\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}124.3\\97.96\\66.36\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}224.5\\176.3\\119.6\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}405.1\\317.4\\215.6\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}730.0\\571.3\\388.2\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.1\\1.2\\1.1\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.7\\2.16\\1.41\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}4.866\\3.888\\2.625\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}8.851\\6.998\\4.735\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}16.01\\12.6\\8.542\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}28.91\\22.67\\15.39\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}52.13\\40.81\\27.73\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}93.92\\73.47\\49.93\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}169.1\\132.2\\89.9\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}304.6\\238.0\\161.8\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}548.3\\428.5\\291.3\end{matrix}\right]\end{gather*}