Hint: the matrix equation will look something like $A\vc{x} = \vc{b}$, where $\vc{b} = \begin{bmatrix} 130\\4\end{bmatrix}$.
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.6\\0.8\\0.0\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}1.76\\2.24\\1.52\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}3.512\\4.248\\3.144\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}6.93\\8.222\\6.285\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}13.62\\16.04\\12.41\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}26.72\\31.38\\24.39\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}52.41\\61.48\\47.87\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}102.7\\120.5\\93.88\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}201.4\\236.2\\184.1\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}394.9\\463.0\\360.8\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}774.1\\907.5\\707.4\end{matrix}\right]\end{gather*}
For the initial condition $\vc{x}_0 = \left[\begin{matrix}1.1\\1.9\\1.4\end{matrix}\right]$, iterating the model forward 10 times gives: \begin{gather*}\vc{x}_1 = \left[\begin{matrix}2.72\\3.3\\2.43\end{matrix}\right], \vc{x}_2 = \left[\begin{matrix}5.371\\6.379\\4.867\end{matrix}\right], \vc{x}_3 = \left[\begin{matrix}10.56\\12.44\\9.617\end{matrix}\right], \vc{x}_4 = \left[\begin{matrix}20.72\\24.33\\18.91\end{matrix}\right], \vc{x}_5 = \left[\begin{matrix}40.63\\47.67\\37.11\end{matrix}\right]\\ \vc{x}_6 = \left[\begin{matrix}79.66\\93.41\\72.78\end{matrix}\right], \vc{x}_7 = \left[\begin{matrix}156.2\\183.1\\142.7\end{matrix}\right], \vc{x}_8 = \left[\begin{matrix}306.1\\358.9\\279.8\end{matrix}\right], \vc{x}_9 = \left[\begin{matrix}600.1\\703.6\\548.4\end{matrix}\right], \vc{x}_{10} = \left[\begin{matrix}1176.0\\1379.0\\1075.0\end{matrix}\right]\end{gather*}