Math Insight

Parametrization of a plane

A plane is determined by a point $\vc{p}$ in the plane and two vectors $\vc{a}$ and $\vc{b}$ parallel to the plane. (This is identical to the case with three points in the plane. Why?)

From this fact, we can parametrize a plane just like we parametrized a line (only we'll need two parameters instead of one). If $\vc{x}$ is a point in the plane, the vector from $\vc{p}$ to $\vc{x}$ (i.e., $\vc{x}-\vc{p}$) is some multiple of $\vc{a}$ plus some multiple of $\vc{b}$. (Can you see why?) We can express this as $\vc{x}-\vc{p} = s\vc{a} + t\vc{b}$ for $t,s \in \vc{R}$. Usually, we'll write this as $\vc{x} = \vc{p} + s\vc{a} + t \vc{b}$. The real numbers $s$ and $t$ are the parameters for this parametrization of the line plane.

The idea of the parametrization is that as the parameters $s$ and $t$ sweep through all real numbers, the point $\vc{x}$ sweeps out the plane. In other words, it is a two-dimensional analogue of the parametrization of the line.

Here we've added the point $\vc{x}$ in black. You can't move $\vc{x}$ directly, but you can move it by changing the parameters $s$ and $t$ (the blue points on sliders).

Clearly, for any value of $s$ and $t$, the point $\vc{x}$ lies on the plane. Also, by changing $s$ and $t$, you can move the point $\vc{x}$ to any position on the plane.

You can see an example of parametrizing a plane here.